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What is the value of capacitance (C) in a series R-L-C circuit, if the circuit resonant frequency is 14.25 MHz and L is 2.84 microhenrys?
44 picofarads
From fr = 1 / (2π√(LC)), C can be found by C = 1 / ((2πfr)^2 L). With fr=14.25MHz and L=2.84µH, C = 1 / ((2π × 14.25e6)^2 × 2.84e-6) ≈ 4.40e-11 F or 44 pF.
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