« Back to Category: Advanced Theory Random (Advanced) Next in Category »
What is the Q of a parallel RLC circuit, if it is resonant at 4.468 MHz, L is 47 microhenrys and R is 180 ohms?
0.136
For a parallel RLC circuit, Q = R / (2πfL). Q = 180 / (2π × 4.468×10^6 × 47×10^-6) ≈ 180 / 1319.0 ≈ 0.136.
Warning: Generated by AI