Radio Amateur Quiz Canadian License

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Question A-003-002-006

What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?

Correct Answer

100 watts

Explanation

Peak Envelope Voltage (PEV) = Vpp / 2 = 200V / 2 = 100V. PEP = (PEV^2) / (2 × R) for a sinusoidal envelope peak, or (V_rms_at_peak)^2/R = ((PEV/√2)^2)/R = PEV^2 / (2R). PEP = (100^2) / (2 × 50) = 10000 / 100 = 100 watts.

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