Radio Amateur Quiz Canadian License

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Question A-003-002-010

What is the output PEP from a transmitter, if an oscilloscope measures 800 volts peak-to-peak across a 50 ohm dummy load connected to the transmitter output?

Correct Answer

1600 watts

Explanation

Peak Envelope Voltage (PEV) = Vpp / 2 = 800V / 2 = 400V. PEP = (PEV^2) / (2 × R) for a sinusoidal envelope peak. PEP = (400^2) / (2 × 50) = 160000 / 100 = 1600 watts.

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