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In a full-wave centre-tap power supply, regardless of load conditions, the peak inverse voltage (PIV) will be _____ times the RMS voltage:
2.8
Each diode in a full-wave center-tap rectifier must withstand approximately twice the peak voltage of half the secondary winding (2 × Vpeak_half_secondary). If Vrms is the voltage of the full secondary, then Vpeak_half_secondary is (Vrms/2) × √2. So PIV ≈ 2 × (Vrms/2) × √2 = Vrms × √2 × √2 = 2 × Vrms, or if Vrms refers to half-winding, then 2 x (Vrms x 1.414) which is 2.8 x Vrms of half-winding.
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