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Assuming a velocity factor of 0.66 what would be the physical length of a typical coaxial stub that is electrically one quarter wavelength long at 14.1 MHz?
3.51 metres (11.5 feet)
Wavelength (λ) in free space = c / f = (300 × 10^6 m/s) / (14.1 × 10^6 Hz) ≈ 21.277 m. Electrical λ/4 = 21.277 / 4 ≈ 5.319 m. Physical length = Electrical length × VF = 5.319 m × 0.66 ≈ 3.51 m. (11.5 feet ≈ 3.505 m).
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