Radio Amateur Quiz Canadian License

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Question A-007-006-001

A transmitter has an output of 100 watts. The cable and connectors have a composite loss of 3 dB, and the antenna has a gain of 6 dBd. What is the Effective Radiated Power?

Correct Answer

200 watts

Explanation

Transmitter power = 100W. Cable loss = 3dB (power ratio 0.5). Power to antenna = 100W * 0.5 = 50W. Antenna gain = 6dBd (power ratio 4, since 3dB is x2, 6dB is x4). ERP = 50W * 4 = 200W. Or, in dB: 10log(100) - 3dB + 6dB = 20dBW - 3dB + 6dB = 23dBW. 10^(23/10) = 10^2.3 ≈ 199.5W ≈ 200W.

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