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If the ohmic resistance of a miniloop antenna is 2 milliohms and the radiation resistance is 50 milliohms, what is the antenna efficiency?
96.15%
Total resistance (Rt) = Radiation resistance (Rr) + Ohmic resistance (Rloss) = 50 mΩ + 2 mΩ = 52 mΩ. Efficiency (η) = (Rr / Rt) × 100% = (50 mΩ / 52 mΩ) × 100% ≈ 0.9615 × 100% ≈ 96.15%.
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