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Two resistors are connected in parallel and are connected across a 40 volt battery. If each resistor is 1000 ohms, the total current is:
80 milliamperes
Method 1: Total Resistance (R_T) for two equal resistors = R/2 = 1000/2 = 500 Ω. Total Current (I_T) = V / R_T = 40 V / 500 Ω = 0.08 A = 80 mA. Method 2: Current in each branch = V/R = 40 V / 1000 Ω = 0.04 A = 40 mA. Total Current = 40 mA + 40 mA = 80 mA.
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