Radio Amateur Quiz Canadian License

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Question A-002-002-009

If a Zener diode rated at 10 V and 50 watts was operated at maximum dissipation rating, it would conduct ____ amperes:

Correct Answer

5

Explanation

Power (P) = Voltage (V) × Current (I). So, I = P / V = 50 watts / 10 volts = 5 amperes.

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