Radio Amateur Quiz Canadian License

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Question A-003-002-005

How is the output Peak-Envelope Power of a transmitter calculated if an oscilloscope is used to measure the Peak-Envelope Voltage across a dummy resistive load (where PEP = Peak-Envelope Power, PEV = Peak-Envelope Voltage, Vp = peak-voltage, RL = load resistance)?

Correct Answer

PEP = [(0.707 PEV)(0.707 PEV)] / RL

Explanation

PEP is calculated from the Peak Envelope Voltage (PEV) as PEP = (V_rms_peak)^2 / RL. Since V_rms_peak = PEV / √2 = 0.707 PEV, squaring this gives (0.707 PEV)^2 / RL, which is (0.707 PEV)(0.707 PEV) / RL.

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